What is the integral from 1 to 4 of (1/x)^2 ?

The integral from 1 to 4 of (1/x)^2 is 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 4 of (1/x)^2

\int_{1}^{4} (\frac{1}{x})^{2} d x

\frac{3}{4}

Decimal

0.75

Solution steps

\int_{1}^{4} (\frac{1}{x})^{2} d x

Simplify

(\frac{1}{x})^{2} : \frac{1}{x ^{2}}

= \int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

= [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

What is the integral from 1 to 4 of (1/x)^2 ?
The integral from 1 to 4 of (1/x)^2 is 3/4