What is the derivative of y=ln(e^{2x}) ?

The derivative of y=ln(e^{2x}) is 2

What is the first derivative of y=ln(e^{2x}) ?

The first derivative of y=ln(e^{2x}) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

y = ln (e^{2 x})

2

Solution steps

\frac{d}{d x} (ln (e^{2 x}))

Simplify

ln (e^{2 x}) : 2 x

= \frac{d}{d x} (2 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 \cdot 1

Simplify

= 2

What is the derivative of y=ln(e^{2x}) ?
The derivative of y=ln(e^{2x}) is 2
What is the first derivative of y=ln(e^{2x}) ?
The first derivative of y=ln(e^{2x}) is 2