What is (\partial)/(\partial x)(cos(4y-2x)) ?

The answer to (\partial)/(\partial x)(cos(4y-2x)) is 2sin(4y-2x)

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(\partial)/(\partial x)(cos(4y-2x))

\frac{\partial}{\partial x} (cos (4 y - 2 x))

2 sin (4 y - 2 x)

Solution steps

\frac{\partial}{\partial x} (cos (4 y - 2 x))

Treat

y

as a constant

Apply the chain rule:

- sin (4 y - 2 x) \frac{\partial}{\partial x} (4 y - 2 x)

= - sin (4 y - 2 x) \frac{\partial}{\partial x} (4 y - 2 x)

\frac{\partial}{\partial x} (4 y - 2 x) = - 2

= - sin (4 y - 2 x) (- 2)

Simplify

= 2 sin (4 y - 2 x)

What is (\partial)/(\partial x)(cos(4y-2x)) ?
The answer to (\partial)/(\partial x)(cos(4y-2x)) is 2sin(4y-2x)