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Popular Calculus >

xy^'-2y=x^2-x-1

Solution

x y^{^{'}} - 2 y = x^{2} - x - 1

Solution

y = x^{2} ln (x) + x + \frac{1}{2} + c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = x^{2} - x - 1

Solve linear ODE:

y = x^{2} ln (x) + x + \frac{1}{2} + c_{1} x^{2}

y = x^{2} ln (x) + x + \frac{1}{2} + c_{1} x^{2}

Graph

Popular Examples

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Frequently Asked Questions (FAQ)

What is the solution for xy^'-2y=x^2-x-1 ?
The solution for xy^'-2y=x^2-x-1 is y=x^2ln(x)+x+1/2+c_{1}x^2