What is the tangent of f(x)= 1/(3+2x),\at x=1 ?

The tangent of f(x)= 1/(3+2x),\at x=1 is y=-2/25 x+7/25

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tangent of f(x)= 1/(3+2x),\at x=1

tangent of

f (x) = \frac{1}{3 + 2 x}, at x = 1

y = - \frac{2}{25} x + \frac{7}{25}

Solution steps

Find the tangent point:

(1, \frac{1}{5})

Find the slope of

f (x) = \frac{1}{3 + 2 x} : \frac{df ( x )}{d x} = - \frac{2}{( 3 + 2 x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{25}

Find the line with slope m=

- \frac{2}{25}

and passing through

(1, \frac{1}{5}) : y = - \frac{2}{25} x + \frac{7}{25}

y = - \frac{2}{25} x + \frac{7}{25}

What is the tangent of f(x)= 1/(3+2x),\at x=1 ?
The tangent of f(x)= 1/(3+2x),\at x=1 is y=-2/25 x+7/25