What is the solution for (xdy)/(dx)-(2dy)/(dx)-(x-2)sin(x)+y=0 ?

The solution for (xdy)/(dx)-(2dy)/(dx)-(x-2)sin(x)+y=0 is y=-cos(x)+(sin(x))/(x-2)+(c_{1})/(x-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(xdy)/(dx)-(2dy)/(dx)-(x-2)sin(x)+y=0

\frac{x d y}{d x} - \frac{2 d y}{d x} - (x - 2) sin (x) + y = 0

y = - cos (x) + \frac{sin ( x )}{x - 2} + \frac{c _{1}}{x - 2}

Solution steps

\frac{x d y}{d x} - \frac{2 d y}{d x} - (x - 2) sin (x) + y = 0

Solve linear ODE:

y = - cos (x) + \frac{sin ( x )}{x - 2} + \frac{c _{1}}{x - 2}

y = - cos (x) + \frac{sin ( x )}{x - 2} + \frac{c _{1}}{x - 2}

What is the solution for (xdy)/(dx)-(2dy)/(dx)-(x-2)sin(x)+y=0 ?
The solution for (xdy)/(dx)-(2dy)/(dx)-(x-2)sin(x)+y=0 is y=-cos(x)+(sin(x))/(x-2)+(c_{1})/(x-2)