What is the integral from 0 to infinity of 1/(x^4-1) ?

The integral from 0 to infinity of 1/(x^4-1) is diverges

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integral from 0 to infinity of 1/(x^4-1)

\int_{0}^{\infty} \frac{1}{x ^{4} - 1} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{x ^{4} - 1} d x

Adjust integral based on undefined pointsThere is an undefined point within the boundaries at

: 1

= \int_{0}^{1} \frac{1}{x ^{4} - 1} d x + \int_{1}^{\infty} \frac{1}{x ^{4} - 1} d x

\int_{0}^{1} \frac{1}{x ^{4} - 1} d x =

diverges

= diverges

What is the integral from 0 to infinity of 1/(x^4-1) ?
The integral from 0 to infinity of 1/(x^4-1) is diverges