What is the tangent of f(x)=5x^2-4x-2,\at x=1 ?

The tangent of f(x)=5x^2-4x-2,\at x=1 is y=6x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=5x^2-4x-2,\at x=1

tangent of

f (x) = 5 x^{2} - 4 x - 2, at x = 1

y = 6 x - 7

Solution steps

Find the tangent point:

(1, - 1)

Find the slope of

f (x) = 5 x^{2} - 4 x - 2 : \frac{df ( x )}{d x} = 10 x - 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(1, - 1) : y = 6 x - 7

y = 6 x - 7

What is the tangent of f(x)=5x^2-4x-2,\at x=1 ?
The tangent of f(x)=5x^2-4x-2,\at x=1 is y=6x-7