What is the derivative of f(x)=(x+2)(2x^2-3) ?

The derivative of f(x)=(x+2)(2x^2-3) is 6x^2+8x-3

What is the first derivative of f(x)=(x+2)(2x^2-3) ?

The first derivative of f(x)=(x+2)(2x^2-3) is 6x^2+8x-3

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derivative of

f (x) = (x + 2) (2 x^{2} - 3)

6 x^{2} + 8 x - 3

Solution steps

\frac{d}{d x} ((x + 2) (2 x^{2} - 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 2, g = 2 x^{2} - 3

= \frac{d}{d x} (x + 2) (2 x^{2} - 3) + \frac{d}{d x} (2 x^{2} - 3) (x + 2)

\frac{d}{d x} (x + 2) = 1

\frac{d}{d x} (2 x^{2} - 3) = 4 x

= 1 \cdot (2 x^{2} - 3) + 4 x (x + 2)

Simplify

1 \cdot (2 x^{2} - 3) + 4 x (x + 2) : 6 x^{2} + 8 x - 3

= 6 x^{2} + 8 x - 3

What is the derivative of f(x)=(x+2)(2x^2-3) ?
The derivative of f(x)=(x+2)(2x^2-3) is 6x^2+8x-3
What is the first derivative of f(x)=(x+2)(2x^2-3) ?
The first derivative of f(x)=(x+2)(2x^2-3) is 6x^2+8x-3