What is the tangent of f(x)=(x-1)/(x-2),\at x=3 ?

The tangent of f(x)=(x-1)/(x-2),\at x=3 is y=-x+5

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tangent of f(x)=(x-1)/(x-2),\at x=3

tangent of

f (x) = \frac{x - 1}{x - 2}, at x = 3

y = - x + 5

Solution steps

Find the tangent point:

(3, 2)

Find the slope of

f (x) = \frac{x - 1}{x - 2} : \frac{df ( x )}{d x} = - \frac{1}{( x - 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(3, 2) : y = - x + 5

y = - x + 5

What is the tangent of f(x)=(x-1)/(x-2),\at x=3 ?
The tangent of f(x)=(x-1)/(x-2),\at x=3 is y=-x+5