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Popular Calculus >

integral from 1 to 2 of (x^2+1)

Solution

\int_{1}^{2} (x^{2} + 1) d x

Solution

\frac{10}{3}

+1

Decimal

3.33333 \dots

Solution steps

\int_{1}^{2} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 1 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 1 d x = 1

= \frac{7}{3} + 1

Simplify

\frac{7}{3} + 1 : \frac{10}{3}

= \frac{10}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^2+1) ?
The integral from 1 to 2 of (x^2+1) is 10/3