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Popular Calculus >

integral from-1 to 2 of (7-3t)

Solution

\int_{- 1}^{2} (7 - 3 t) d t

Solution

\frac{33}{2}

+1

Decimal

16.5

Solution steps

\int_{- 1}^{2} 7 - 3 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 7 d t - \int_{- 1}^{2} 3 t d t

\int_{- 1}^{2} 7 d t = 21

\int_{- 1}^{2} 3 t d t = \frac{9}{2}

= 21 - \frac{9}{2}

Simplify

21 - \frac{9}{2} : \frac{33}{2}

= \frac{33}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (7-3t) ?
The integral from-1 to 2 of (7-3t) is 33/2