integral from-1 to 2 of (7-3t)

Lösung

\int_{- 1}^{2} (7 - 3 t) d t

\frac{33}{2}

Dezimale

16.5

Schritte zur Lösung

\int_{- 1}^{2} 7 - 3 t d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 7 d t - \int_{- 1}^{2} 3 t d t

\int_{- 1}^{2} 7 d t = 21

\int_{- 1}^{2} 3 t d t = \frac{9}{2}

= 21 - \frac{9}{2}

Vereinfache

21 - \frac{9}{2} : \frac{33}{2}

= \frac{33}{2}

s l o p e in t erce pt (- 7, - 3), (- 5, - 8)

t an g e n t 2 - x^{2}

\frac{d}{d t} (a cos (w (t) t) + b sin (w (t) t))

\frac{d}{d x} (ln (\frac{x ^{3}}{x ^{5} + 1}))

d er i v a t i v e y = 10 + tan^{2} (x)