What is the derivative of x^2+3x+sqrt(4) ?

The derivative of x^2+3x+sqrt(4) is 2x+3

What is the first derivative of x^2+3x+sqrt(4) ?

The first derivative of x^2+3x+sqrt(4) is 2x+3

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\frac{d}{d x} (x^{2} + 3 x + 4)

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 4)

Simplify

x^{2} + 3 x + 4 : x^{2} + 3 x + 2

= \frac{d}{d x} (x^{2} + 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

What is the derivative of x^2+3x+sqrt(4) ?
The derivative of x^2+3x+sqrt(4) is 2x+3
What is the first derivative of x^2+3x+sqrt(4) ?
The first derivative of x^2+3x+sqrt(4) is 2x+3