What is the solution for x^2y^{''}+2xy^'-20y=0 ?

The solution for x^2y^{''}+2xy^'-20y=0 is y=c_{1}x^4+(c_{2})/(x^5)

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x^2y^{''}+2xy^'-20y=0

x^{2} y^{^{''}} + 2 x y^{^{'}} - 20 y = 0

y = c_{1} x^{4} + \frac{c _{2}}{x ^{5}}

Solution steps

x^{2} y^{''} (x) + 2 x y^{'} (x) - 20 y = 0

Solve linear ODE:

y = c_{1} x^{4} + \frac{c _{2}}{x ^{5}}

y = c_{1} x^{4} + \frac{c _{2}}{x ^{5}}

What is the solution for x^2y^{''}+2xy^'-20y=0 ?
The solution for x^2y^{''}+2xy^'-20y=0 is y=c_{1}x^4+(c_{2})/(x^5)