What is the tangent of f(x)=x^2+ax+2,\at x=1 ?

The tangent of f(x)=x^2+ax+2,\at x=1 is y=(2+a)x+1

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tangent of f(x)=x^2+ax+2,\at x=1

tangent of

f (x) = x^{2} + a x + 2, at x = 1

y = (2 + a) x + 1

Solution steps

Find the tangent point:

(1, a + 3)

Find the slope of

f (x) = x^{2} + a x + 2 : \frac{df ( x )}{d x} = 2 x + a

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 + a

Find the line with slope m=

2 + a

and passing through

(1, a + 3) : y = (2 + a) x + 1

y = (2 + a) x + 1

What is the tangent of f(x)=x^2+ax+2,\at x=1 ?
The tangent of f(x)=x^2+ax+2,\at x=1 is y=(2+a)x+1