What is the solution for y^'=(x-2)/(y+1) ?

The solution for y^'=(x-2)/(y+1) is y=-1+sqrt(x^2-4x+c_{1)+1},y=-sqrt(x^2-4x+c_{1)+1}-1

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y^'=(x-2)/(y+1)

y^{^{'}} = \frac{x - 2}{y + 1}

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

Solution steps

y^{'} (x) = \frac{x - 2}{y + 1}

Solve separable ODE:

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

What is the solution for y^'=(x-2)/(y+1) ?
The solution for y^'=(x-2)/(y+1) is y=-1+sqrt(x^2-4x+c_{1)+1},y=-sqrt(x^2-4x+c_{1)+1}-1