What is the derivative of f(x)=(x+1810)/(70(x+2)) ?

The derivative of f(x)=(x+1810)/(70(x+2)) is -(904)/(35(x+2)^2)

What is the first derivative of f(x)=(x+1810)/(70(x+2)) ?

The first derivative of f(x)=(x+1810)/(70(x+2)) is -(904)/(35(x+2)^2)

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derivative of

f (x) = \frac{x + 1810}{70 ( x + 2 )}

- \frac{904}{35 ( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 1810}{70 ( x + 2 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{70} \frac{d}{d x} (\frac{x + 1810}{x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{70} \cdot \frac{\frac{d}{d x} ( x + 1810 ) ( x + 2 ) - \frac{d}{d x} ( x + 2 ) ( x + 1810 )}{( x + 2 ) ^{2}}

\frac{d}{d x} (x + 1810) = 1

\frac{d}{d x} (x + 2) = 1

= \frac{1}{70} \cdot \frac{1 \cdot ( x + 2 ) - 1 \cdot ( x + 1810 )}{( x + 2 ) ^{2}}

Simplify

\frac{1}{70} \cdot \frac{1 \cdot ( x + 2 ) - 1 \cdot ( x + 1810 )}{( x + 2 ) ^{2}} : - \frac{904}{35 ( x + 2 ) ^{2}}

= - \frac{904}{35 ( x + 2 ) ^{2}}

What is the derivative of f(x)=(x+1810)/(70(x+2)) ?
The derivative of f(x)=(x+1810)/(70(x+2)) is -(904)/(35(x+2)^2)
What is the first derivative of f(x)=(x+1810)/(70(x+2)) ?
The first derivative of f(x)=(x+1810)/(70(x+2)) is -(904)/(35(x+2)^2)