What is the derivative of ln(sec(2x)+tan(2x)) ?

The derivative of ln(sec(2x)+tan(2x)) is 2sec(2x)

What is the first derivative of ln(sec(2x)+tan(2x)) ?

The first derivative of ln(sec(2x)+tan(2x)) is 2sec(2x)

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derivative of

ln (sec (2 x) + tan (2 x))

2 sec (2 x)

Solution steps

\frac{d}{d x} (ln (sec (2 x) + tan (2 x)))

Apply the chain rule:

\frac{1}{sec ( 2 x ) + tan ( 2 x )} \frac{d}{d x} (sec (2 x) + tan (2 x))

= \frac{1}{sec ( 2 x ) + tan ( 2 x )} \frac{d}{d x} (sec (2 x) + tan (2 x))

\frac{d}{d x} (sec (2 x) + tan (2 x)) = sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2

= \frac{1}{sec ( 2 x ) + tan ( 2 x )} (sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2)

Simplify

\frac{1}{sec ( 2 x ) + tan ( 2 x )} (sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2) : 2 sec (2 x)

= 2 sec (2 x)

What is the derivative of ln(sec(2x)+tan(2x)) ?
The derivative of ln(sec(2x)+tan(2x)) is 2sec(2x)
What is the first derivative of ln(sec(2x)+tan(2x)) ?
The first derivative of ln(sec(2x)+tan(2x)) is 2sec(2x)