What is the solution for (dy)/(dx)+y+2cos(x)=0 ?

The solution for (dy)/(dx)+y+2cos(x)=0 is y=-sin(x)-cos(x)+(c_{1})/(e^x)

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(dy)/(dx)+y+2cos(x)=0

\frac{d y}{d x} + y + 2 cos (x) = 0

y = - sin (x) - cos (x) + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d y}{d x} + y + 2 cos (x) = 0

Solve linear ODE:

y = - sin (x) - cos (x) + \frac{c _{1}}{e ^{x}}

y = - sin (x) - cos (x) + \frac{c _{1}}{e ^{x}}

What is the solution for (dy)/(dx)+y+2cos(x)=0 ?
The solution for (dy)/(dx)+y+2cos(x)=0 is y=-sin(x)-cos(x)+(c_{1})/(e^x)