What is the derivative of e^{2x}+x^2-16 ?

The derivative of e^{2x}+x^2-16 is 2x+2e^{2x}

What is the first derivative of e^{2x}+x^2-16 ?

The first derivative of e^{2x}+x^2-16 is 2x+2e^{2x}

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\frac{d}{d x} (e^{2 x} + x^{2} - 16)

2 x + 2 e^{2 x}

Solution steps

\frac{d}{d x} (e^{2 x} + x^{2} - 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (16)

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (16) = 0

= e^{2 x} \cdot 2 + 2 x - 0

Simplify

= 2 x + 2 e^{2 x}

What is the derivative of e^{2x}+x^2-16 ?
The derivative of e^{2x}+x^2-16 is 2x+2e^{2x}
What is the first derivative of e^{2x}+x^2-16 ?
The first derivative of e^{2x}+x^2-16 is 2x+2e^{2x}