What is the integral from-1 to 1 of pi(x^2+1)^2 ?

The integral from-1 to 1 of pi(x^2+1)^2 is pi 56/15

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integral from-1 to 1 of pi(x^2+1)^2

\int_{- 1}^{1} π (x^{2} + 1)^{2} d x

π \frac{56}{15}

Decimal

11.72861 \dots

Solution steps

\int_{- 1}^{1} π (x^{2} + 1)^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{- 1}^{1} (x^{2} + 1)^{2} d x

Expand

(x^{2} + 1)^{2} : x^{4} + 2 x^{2} + 1

= π \cdot \int_{- 1}^{1} x^{4} + 2 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{- 1}^{1} x^{4} d x + \int_{- 1}^{1} 2 x^{2} d x + \int_{- 1}^{1} 1 d x)

\int_{- 1}^{1} x^{4} d x = \frac{2}{5}

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

\int_{- 1}^{1} 1 d x = 2

= π (\frac{2}{5} + \frac{4}{3} + 2)

Join

\frac{2}{5} + \frac{4}{3} + 2 : \frac{56}{15}

= π \frac{56}{15}

What is the integral from-1 to 1 of pi(x^2+1)^2 ?
The integral from-1 to 1 of pi(x^2+1)^2 is pi 56/15