What is the solution for (tdy)/(dt)=t^3+23t^3y ?

The solution for (tdy)/(dt)=t^3+23t^3y is y=(e^{(23t^3+c_{1})/3})/(23)-1/23

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(tdy)/(dt)=t^3+23t^3y

\frac{t d y}{d t} = t^{3} + 23 t^{3} y

y = \frac{e ^{\frac{23 t ^{3} + c _{1}}{3}}}{23} - \frac{1}{23}

Solution steps

\frac{t d y}{d t} = t^{3} + 23 t^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{23 t ^{3} + c _{1}}{3}}}{23} - \frac{1}{23}

y = \frac{e ^{\frac{23 t ^{3} + c _{1}}{3}}}{23} - \frac{1}{23}

What is the solution for (tdy)/(dt)=t^3+23t^3y ?
The solution for (tdy)/(dt)=t^3+23t^3y is y=(e^{(23t^3+c_{1})/3})/(23)-1/23