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Popular Calculus >

integral from-2pi to 2pi of pisin^2(x)

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Solution

∫−2π2π​πsin2(x)dx

Solution

2π2
+1
Decimal
19.73920…
Solution steps
∫−2π2π​πsin2(x)dx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=π⋅∫−2π2π​sin2(x)dx
Rewrite using trig identities
=π⋅∫−2π2π​21−cos(2x)​dx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=π21​⋅∫−2π2π​1−cos(2x)dx
Apply the Sum Rule: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=π21​(∫−2π2π​1dx−∫−2π2π​cos(2x)dx)
∫−2π2π​1dx=4π
∫−2π2π​cos(2x)dx=0
=π21​(4π−0)
Simplify π21​(4π−0):2π2
=2π2

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Frequently Asked Questions (FAQ)

  • What is the integral from-2pi to 2pi of pisin^2(x) ?

    The integral from-2pi to 2pi of pisin^2(x) is 2pi^2
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