What is the tangent of y=(4x+5)/(x-1),(2,13) ?

The tangent of y=(4x+5)/(x-1),(2,13) is y=-9x+31

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tangent of y=(4x+5)/(x-1),(2,13)

tangent of

y = \frac{4 x + 5}{x - 1}, (2, 13)

y = - 9 x + 31

Solution steps

Find the slope of

y = \frac{4 x + 5}{x - 1} : \frac{d y}{d x} = - \frac{9}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 9

Find the line with slope m=

- 9

and passing through

(2, 13) : y = - 9 x + 31

y = - 9 x + 31

What is the tangent of y=(4x+5)/(x-1),(2,13) ?
The tangent of y=(4x+5)/(x-1),(2,13) is y=-9x+31