What is the tangent of f(x)=5-2x^2,\at x=-2 ?

The tangent of f(x)=5-2x^2,\at x=-2 is y=8x+13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=5-2x^2,\at x=-2

tangent of

f (x) = 5 - 2 x^{2}, at x = - 2

y = 8 x + 13

Solution steps

Find the tangent point:

(- 2, - 3)

Find the slope of

f (x) = 5 - 2 x^{2} : \frac{df ( x )}{d x} = - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(- 2, - 3) : y = 8 x + 13

y = 8 x + 13

What is the tangent of f(x)=5-2x^2,\at x=-2 ?
The tangent of f(x)=5-2x^2,\at x=-2 is y=8x+13