What is area y=(x-2)^2-4,y=x+1 ?

The answer to area y=(x-2)^2-4,y=x+1 is sqrt(29)+(23sqrt(29))/6

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area y=(x-2)^2-4,y=x+1

area

y = (x - 2)^{2} - 4, y = x + 1

29 + \frac{23 29}{6}

Decimal

26.02829 \dots

Solution steps

Apply the area formula:

\int_{\frac{5 - 29}{2}}^{\frac{5 + 29}{2}} (x - 2)^{2} - 4 - (x + 1) d x

Solve

\int_{\frac{5 - 29}{2}}^{\frac{5 + 29}{2}} (x - 2)^{2} - 4 - (x + 1) d x : 29 + \frac{23 29}{6}

The area is:

= 29 + \frac{23 29}{6}

What is area y=(x-2)^2-4,y=x+1 ?
The answer to area y=(x-2)^2-4,y=x+1 is sqrt(29)+(23sqrt(29))/6