What is the tangent of y=sin(2x),\at x= pi/2 ?

The tangent of y=sin(2x),\at x= pi/2 is y=-2x+pi

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tangent of y=sin(2x),\at x= pi/2

tangent of

y = sin (2 x), at x = \frac{π}{2}

y = - 2 x + π

Solution steps

Find the tangent point:

(\frac{π}{2}, 0)

Find the slope of

y = sin (2 x) : \frac{d y}{d x} = cos (2 x) \cdot 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{π}{2}, 0) : y = - 2 x + π

y = - 2 x + π

What is the tangent of y=sin(2x),\at x= pi/2 ?
The tangent of y=sin(2x),\at x= pi/2 is y=-2x+pi