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tangent x/(sqrt(4+x^2))

解答

切线

\frac{x}{4 + x ^{2}}

解答

y = \frac{4}{( 4 + a _{0}^{2} ) 4 + a _{0}^{2}} x + \frac{a _{0}^{3}}{( a _{0}^{2} + 4 ) a _{0}^{2} + 4}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{a _{0}}{4 + a _{0}^{2}})

计算

y = \frac{x}{4 + x ^{2}}

的斜率:

\frac{d y}{d x} = \frac{4}{( 4 + x ^{2} ) 4 + x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{4}{( 4 + a _{0}^{2} ) 4 + a _{0}^{2}}

找到斜率 m=

\frac{4}{( 4 + a _{0}^{2} ) 4 + a _{0}^{2}}

且穿过

(a_{0}, \frac{a _{0}}{4 + a _{0}^{2}})

的直线:

y = \frac{4}{( 4 + a _{0}^{2} ) 4 + a _{0}^{2}} x + \frac{a _{0}^{3}}{( a _{0}^{2} + 4 ) a _{0}^{2} + 4}

y = \frac{4}{( 4 + a _{0}^{2} ) 4 + a _{0}^{2}} x + \frac{a _{0}^{3}}{( a _{0}^{2} + 4 ) a _{0}^{2} + 4}

作图

流行的例子

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