What is the derivative of y=3x^3+45x^2+81x ?

The derivative of y=3x^3+45x^2+81x is 9x^2+90x+81

What is the first derivative of y=3x^3+45x^2+81x ?

The first derivative of y=3x^3+45x^2+81x is 9x^2+90x+81

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derivative of

y = 3 x^{3} + 45 x^{2} + 81 x

9 x^{2} + 90 x + 81

Solution steps

\frac{d}{d x} (3 x^{3} + 45 x^{2} + 81 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (45 x^{2}) + \frac{d}{d x} (81 x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (45 x^{2}) = 90 x

\frac{d}{d x} (81 x) = 81

= 9 x^{2} + 90 x + 81

What is the derivative of y=3x^3+45x^2+81x ?
The derivative of y=3x^3+45x^2+81x is 9x^2+90x+81
What is the first derivative of y=3x^3+45x^2+81x ?
The first derivative of y=3x^3+45x^2+81x is 9x^2+90x+81