derivative f(x)=x^3ln(x)

解

導関数

f (x) = x^{3} ln (x)

3 x^{2} ln (x) + x^{2}

解答ステップ

\frac{d}{d x} (x^{3} ln (x))

積の法則を適用:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = ln (x)

= \frac{d}{d x} (x^{3}) ln (x) + \frac{d}{d x} (ln (x)) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 3 x^{2} ln (x) + \frac{1}{x} x^{3}

\frac{1}{x} x^{3} = x^{2}

= 3 x^{2} ln (x) + x^{2}