y^'+y/x =2x^4y^2

解答

y^{^{'}} + \frac{y}{x} = 2 x^{4} y^{2}

y = \frac{2}{x ( - x ^{4} + c _{1} )}

求解步骤

y^{'} (x) + \frac{y}{x} = 2 x^{4} y^{2}

求解贝努力方程:

y = \frac{2}{x ( - x ^{4} + c _{1} )}

y = \frac{2}{x ( - x ^{4} + c _{1} )}

\frac{d}{d x} (e^{c o s (4 x)})

s l o p e (6.3) (7.8)

t an g e n t 33 x^{3}

\int \frac{a + b x ^{7}}{8 a x + b x ^{8}} d x

t an g e n t f (x) = 4 e^{x} + x, at x = 0