What is the integral of (ln(y))^2 ?

The integral of (ln(y))^2 is yln^2(y)-2(yln(y)-y)+C

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integral of (ln(y))^2

\int (ln (y))^{2} d y

y ln^{2} (y) - 2 (y ln (y) - y) + C

Solution steps

\int (ln (y))^{2} d y

Apply Integration By Parts

= y ln^{2} (y) - \int 2 ln (y) d y

\int 2 ln (y) d y = 2 (y ln (y) - y)

= y ln^{2} (y) - 2 (y ln (y) - y)

Add a constant to the solution

= y ln^{2} (y) - 2 (y ln (y) - y) + C

What is the integral of (ln(y))^2 ?
The integral of (ln(y))^2 is yln^2(y)-2(yln(y)-y)+C