What is area y= 2/3 x^{3/2}+3,[0,2] ?

The answer to area y= 2/3 x^{3/2}+3,[0,2] is (16*2^{1/2})/(15)+6

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area y= 2/3 x^{3/2}+3,[0,2]

area

y = \frac{2}{3} x^{\frac{3}{2}} + 3, [0, 2]

\frac{16 \cdot 2 ^{\frac{1}{2}}}{15} + 6

Decimal

7.50849 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} \frac{2}{3} x^{\frac{3}{2}} + 3 d x

Solve

\int_{0}^{2} \frac{2}{3} x^{\frac{3}{2}} + 3 d x : \frac{16 \cdot 2 ^{\frac{1}{2}}}{15} + 6

The area is:

= \frac{16 \cdot 2 ^{\frac{1}{2}}}{15} + 6

What is area y= 2/3 x^{3/2}+3,[0,2] ?
The answer to area y= 2/3 x^{3/2}+3,[0,2] is (16*2^{1/2})/(15)+6