What is the derivative of 6+cos(sqrt(3x)) ?

The derivative of 6+cos(sqrt(3x)) is -(sqrt(3)sin(sqrt(3)sqrt(x)))/(2sqrt(x))

What is the first derivative of 6+cos(sqrt(3x)) ?

The first derivative of 6+cos(sqrt(3x)) is -(sqrt(3)sin(sqrt(3)sqrt(x)))/(2sqrt(x))

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\frac{d}{d x} (6 + cos (3 x))

- \frac{3 sin ( 3 x )}{2 x}

Solution steps

\frac{d}{d x} (6 + cos (3 x))

Simplify

6 + cos (3 x) : 6 + cos (3 x)

= \frac{d}{d x} (6 + cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6) + \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (6) = 0

\frac{d}{d x} (cos (3 x)) = - \frac{3 sin ( 3 x )}{2 x}

= 0 - \frac{3 sin ( 3 x )}{2 x}

Simplify

= - \frac{3 sin ( 3 x )}{2 x}

What is the derivative of 6+cos(sqrt(3x)) ?
The derivative of 6+cos(sqrt(3x)) is -(sqrt(3)sin(sqrt(3)sqrt(x)))/(2sqrt(x))
What is the first derivative of 6+cos(sqrt(3x)) ?
The first derivative of 6+cos(sqrt(3x)) is -(sqrt(3)sin(sqrt(3)sqrt(x)))/(2sqrt(x))