What is the solution for f^'(x)=(x^2+3)/(cos(x)) ?

The solution for f^'(x)=(x^2+3)/(cos(x)) is f(x)=integral of (x^2+3)/(cos(x))

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f^'(x)=(x^2+3)/(cos(x))

f^{^{'}} (x) = \frac{x ^{2} + 3}{cos ( x )}

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

Solution steps

f^{'} (x) = \frac{x ^{2} + 3}{cos ( x )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

What is the solution for f^'(x)=(x^2+3)/(cos(x)) ?
The solution for f^'(x)=(x^2+3)/(cos(x)) is f(x)=integral of (x^2+3)/(cos(x))