What is the tangent of f(x)= 4/(3x-1),\at x=3 ?

The tangent of f(x)= 4/(3x-1),\at x=3 is y=-3/16 x+17/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)= 4/(3x-1),\at x=3

tangent of

f (x) = \frac{4}{3 x - 1}, at x = 3

y = - \frac{3}{16} x + \frac{17}{16}

Solution steps

Find the tangent point:

(3, \frac{1}{2})

Find the slope of

f (x) = \frac{4}{3 x - 1} : \frac{df ( x )}{d x} = - \frac{12}{( 3 x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{16}

Find the line with slope m=

- \frac{3}{16}

and passing through

(3, \frac{1}{2}) : y = - \frac{3}{16} x + \frac{17}{16}

y = - \frac{3}{16} x + \frac{17}{16}

What is the tangent of f(x)= 4/(3x-1),\at x=3 ?
The tangent of f(x)= 4/(3x-1),\at x=3 is y=-3/16 x+17/16