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Popular Calculus >

derivative of 3ax^4-4ax^3-5bx^2+7cx

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Solution

dxd​(3ax4−4ax3−5bx2+7cx)

Solution

12ax3−12ax2−10bx+7c
Solution steps
dxd​(3ax4−4ax3−5bx2+7cx)
Apply the Sum/Difference Rule: (f±g)′=f′±g′=dxd​(3ax4)−dxd​(4ax3)−dxd​(5bx2)+dxd​(7cx)
dxd​(3ax4)=12ax3
dxd​(4ax3)=12ax2
dxd​(5bx2)=10bx
dxd​(7cx)=7c
=12ax3−12ax2−10bx+7c

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Popular Examples

integral of (1/(x^{-3)}+x^2e^{3x^3}-8/x)y^'+6y=e^{-t}-6integral of e^{4x}-5sin(x)tangent of f(x)= 8/(x^2+4)integral of 3x^3+4x^2-5x

Frequently Asked Questions (FAQ)

  • What is the derivative of 3ax^4-4ax^3-5bx^2+7cx ?

    The derivative of 3ax^4-4ax^3-5bx^2+7cx is 12ax^3-12ax^2-10bx+7c
  • What is the first derivative of 3ax^4-4ax^3-5bx^2+7cx ?

    The first derivative of 3ax^4-4ax^3-5bx^2+7cx is 12ax^3-12ax^2-10bx+7c
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