What is the solution for (e^x+e^{-x})(dy)/(dx)=y^2 ?

The solution for (e^x+e^{-x})(dy)/(dx)=y^2 is y=-1/(arctan(e^x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(e^x+e^{-x})(dy)/(dx)=y^2

(e^{x} + e^{- x}) \frac{d y}{d x} = y^{2}

y = - \frac{1}{arctan ( e ^{x} ) + c _{1}}

Solution steps

(e^{x} + e^{- x}) \frac{d y}{d x} = y^{2}

Solve separable ODE:

y = - \frac{1}{arctan ( e ^{x} ) + c _{1}}

y = - \frac{1}{arctan ( e ^{x} ) + c _{1}}

What is the solution for (e^x+e^{-x})(dy)/(dx)=y^2 ?
The solution for (e^x+e^{-x})(dy)/(dx)=y^2 is y=-1/(arctan(e^x)+c_{1)}