What is the integral of pi/(1.2-2x) ?

The integral of pi/(1.2-2x) is -pi/2 ln|1.2-2x|+C

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integral of pi/(1.2-2x)

\int \frac{π}{1.2 - 2 x} d x

- \frac{π}{2} ln ∣ 1.2 - 2 x ∣ + C

Solution steps

\int \frac{π}{1.2 - 2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int \frac{1}{1.2 - 2 x} d x

Apply u-substitution

= π \cdot \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π (- \frac{1}{2} \cdot \int \frac{1}{u} d u)

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= π (- \frac{1}{2} ln ∣ u ∣)

Substitute back

u = 1.2 - 2 x

= π (- \frac{1}{2} ln ∣ 1.2 - 2 x ∣)

Simplify

π (- \frac{1}{2} ln ∣ 1.2 - 2 x ∣) : - \frac{π}{2} ln ∣ 1.2 - 2 x ∣

= - \frac{π}{2} ln ∣ 1.2 - 2 x ∣

Add a constant to the solution

= - \frac{π}{2} ln ∣ 1.2 - 2 x ∣ + C

What is the integral of pi/(1.2-2x) ?
The integral of pi/(1.2-2x) is -pi/2 ln|1.2-2x|+C