What is the integral of 2+6x-3x^2 ?

The integral of 2+6x-3x^2 is 2x+3x^2-x^3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2+6x-3x^2

\int 2 + 6 x - 3 x^{2} d x

2 x + 3 x^{2} - x^{3} + C

Solution steps

\int 2 + 6 x - 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x + \int 6 x d x - \int 3 x^{2} d x

\int 2 d x = 2 x

\int 6 x d x = 3 x^{2}

\int 3 x^{2} d x = x^{3}

= 2 x + 3 x^{2} - x^{3}

Add a constant to the solution

= 2 x + 3 x^{2} - x^{3} + C