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Popular Calculus >

area x^2=4y,3x-4y+4=0

Solution

area

x^{2} = 4 y, 3 x - 4 y + 4 = 0

Solution

\frac{125}{24}

+1

Decimal

5.20833 \dots

Solution steps

Isolate

y

for

x^{2} = 4 y : y = \frac{x ^{2}}{4}

Isolate

y

for

3 x - 4 y + 4 = 0 : y = - \frac{- 3 x - 4}{4}

Apply the area formula:

\int_{- 1}^{4} \frac{x ^{2}}{4} + \frac{1}{4} (- 3 x - 4) d x

Solve

\int_{- 1}^{4} \frac{x ^{2}}{4} + \frac{1}{4} (- 3 x - 4) d x : \frac{125}{24}

The area is:

= \frac{125}{24}

Graph

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Frequently Asked Questions (FAQ)

What is area x^2=4y,3x-4y+4=0 ?
The answer to area x^2=4y,3x-4y+4=0 is 125/24