What is the derivative of 35+35sin((-2pit-pi)/2) ?

The derivative of 35+35sin((-2pit-pi)/2) is -35picos((-2pit-pi)/2)

What is the first derivative of 35+35sin((-2pit-pi)/2) ?

The first derivative of 35+35sin((-2pit-pi)/2) is -35picos((-2pit-pi)/2)

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derivative of

35 + 35 sin (\frac{- 2 π t - π}{2})

- 35 π cos (\frac{- 2 π t - π}{2})

Solution steps

\frac{d}{d t} (35 + 35 sin (\frac{- 2 π t - π}{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (35) + \frac{d}{d t} (35 sin (\frac{- 2 π t - π}{2}))

\frac{d}{d t} (35) = 0

\frac{d}{d t} (35 sin (\frac{- 2 π t - π}{2})) = - 35 π cos (\frac{- 2 π t - π}{2})

= 0 - 35 π cos (\frac{- 2 π t - π}{2})

Simplify

= - 35 π cos (\frac{- 2 π t - π}{2})

What is the derivative of 35+35sin((-2pit-pi)/2) ?
The derivative of 35+35sin((-2pit-pi)/2) is -35picos((-2pit-pi)/2)
What is the first derivative of 35+35sin((-2pit-pi)/2) ?
The first derivative of 35+35sin((-2pit-pi)/2) is -35picos((-2pit-pi)/2)