What is the tangent of f(x)=x^3-9x+5,\at x=3 ?

The tangent of f(x)=x^3-9x+5,\at x=3 is y=18x-49

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tangent of f(x)=x^3-9x+5,\at x=3

tangent of

f (x) = x^{3} - 9 x + 5, at x = 3

y = 18 x - 49

Solution steps

Find the tangent point:

(3, 5)

Find the slope of

f (x) = x^{3} - 9 x + 5 : \frac{df ( x )}{d x} = 3 x^{2} - 9

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 18

Find the line with slope m=

18

and passing through

(3, 5) : y = 18 x - 49

y = 18 x - 49

What is the tangent of f(x)=x^3-9x+5,\at x=3 ?
The tangent of f(x)=x^3-9x+5,\at x=3 is y=18x-49