What is the derivative of f(x)= A/(x^7)+Be^7 ?

The derivative of f(x)= A/(x^7)+Be^7 is -(7A)/(x^8)

What is the first derivative of f(x)= A/(x^7)+Be^7 ?

The first derivative of f(x)= A/(x^7)+Be^7 is -(7A)/(x^8)

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derivative of

f (x) = \frac{A}{x ^{7}} + B e^{7}

- \frac{7 A}{x ^{8}}

Solution steps

\frac{d}{d x} (\frac{A}{x ^{7}} + B e^{7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{A}{x ^{7}}) + \frac{d}{d x} (B e^{7})

\frac{d}{d x} (\frac{A}{x ^{7}}) = - \frac{7 A}{x ^{8}}

\frac{d}{d x} (B e^{7}) = 0

= - \frac{7 A}{x ^{8}} + 0

Simplify

= - \frac{7 A}{x ^{8}}

What is the derivative of f(x)= A/(x^7)+Be^7 ?
The derivative of f(x)= A/(x^7)+Be^7 is -(7A)/(x^8)
What is the first derivative of f(x)= A/(x^7)+Be^7 ?
The first derivative of f(x)= A/(x^7)+Be^7 is -(7A)/(x^8)