What is the derivative of (16/(x^2)) ?

The derivative of (16/(x^2)) is -(32)/(x^3)

What is the first derivative of (16/(x^2)) ?

The first derivative of (16/(x^2)) is -(32)/(x^3)

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\frac{d}{d x} (\frac{16}{x ^{2}})

- \frac{32}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{16}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 16 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 (- 2 x^{- 2 - 1})

Simplify

16 (- 2 x^{- 2 - 1}) : - \frac{32}{x ^{3}}

= - \frac{32}{x ^{3}}

What is the derivative of (16/(x^2)) ?
The derivative of (16/(x^2)) is -(32)/(x^3)
What is the first derivative of (16/(x^2)) ?
The first derivative of (16/(x^2)) is -(32)/(x^3)