What is the tangent of f(x)=8x-x^2,(1,7) ?

The tangent of f(x)=8x-x^2,(1,7) is y=6x+1

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tangent of f(x)=8x-x^2,(1,7)

tangent of

f (x) = 8 x - x^{2}, (1, 7)

y = 6 x + 1

Solution steps

Find the slope of

f (x) = 8 x - x^{2} : \frac{df ( x )}{d x} = 8 - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(1, 7) : y = 6 x + 1

y = 6 x + 1

What is the tangent of f(x)=8x-x^2,(1,7) ?
The tangent of f(x)=8x-x^2,(1,7) is y=6x+1