What is the solution for 2(sin(t)y^'+cos(t)y)=cos(t)sin^3(t) ?

The solution for 2(sin(t)y^'+cos(t)y)=cos(t)sin^3(t) is y=(sin^3(t))/8+(c_{1})/(sin(t))

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2(sin(t)y^'+cos(t)y)=cos(t)sin^3(t)

2 (sin (t) y^{^{'}} + cos (t) y) = cos (t) sin^{3} (t)

y = \frac{sin ^{3} ( t )}{8} + \frac{c _{1}}{sin ( t )}

Solution steps

2 (sin (t) y^{'} (t) + cos (t) y) = cos (t) sin^{3} (t)

Solve linear ODE:

y = \frac{sin ^{3} ( t )}{8} + \frac{c _{1}}{sin ( t )}

y = \frac{sin ^{3} ( t )}{8} + \frac{c _{1}}{sin ( t )}

What is the solution for 2(sin(t)y^'+cos(t)y)=cos(t)sin^3(t) ?
The solution for 2(sin(t)y^'+cos(t)y)=cos(t)sin^3(t) is y=(sin^3(t))/8+(c_{1})/(sin(t))