What is the derivative of x^3-6x^2-15x+4 ?

The derivative of x^3-6x^2-15x+4 is 3x^2-12x-15

What is the first derivative of x^3-6x^2-15x+4 ?

The first derivative of x^3-6x^2-15x+4 is 3x^2-12x-15

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derivative of

x^{3} - 6 x^{2} - 15 x + 4

3 x^{2} - 12 x - 15

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} - 15 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (15 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (15 x) = 15

\frac{d}{d x} (4) = 0

= 3 x^{2} - 12 x - 15 + 0

Simplify

= 3 x^{2} - 12 x - 15

What is the derivative of x^3-6x^2-15x+4 ?
The derivative of x^3-6x^2-15x+4 is 3x^2-12x-15
What is the first derivative of x^3-6x^2-15x+4 ?
The first derivative of x^3-6x^2-15x+4 is 3x^2-12x-15