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Popular Calculus >

integral from 1 to 4 of (x/2)+1

Solution

\int_{1}^{4} (\frac{x}{2}) + 1 d x

Solution

\frac{27}{4}

+1

Decimal

6.75

Solution steps

\int_{1}^{4} \frac{x}{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} \frac{x}{2} d x + \int_{1}^{4} 1 d x

\int_{1}^{4} \frac{x}{2} d x = \frac{15}{4}

\int_{1}^{4} 1 d x = 3

= \frac{15}{4} + 3

Simplify

\frac{15}{4} + 3 : \frac{27}{4}

= \frac{27}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (x/2)+1 ?
The integral from 1 to 4 of (x/2)+1 is 27/4