What is the solution for y^'+(1-1/x)y=x^2 ?

The solution for y^'+(1-1/x)y=x^2 is y=x^2-x+(c_{1}x)/(e^{x+c_{1)}}

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y^'+(1-1/x)y=x^2

y^{^{'}} + (1 - \frac{1}{x}) y = x^{2}

y = x^{2} - x + \frac{c _{1} x}{e ^{x + c_{1}}}

Solution steps

y^{'} (x) + (1 - \frac{1}{x}) y = x^{2}

Solve linear ODE:

y = x^{2} - x + \frac{c _{1} x}{e ^{x + c_{1}}}

y = x^{2} - x + \frac{c _{1} x}{e ^{x + c_{1}}}

What is the solution for y^'+(1-1/x)y=x^2 ?
The solution for y^'+(1-1/x)y=x^2 is y=x^2-x+(c_{1}x)/(e^{x+c_{1)}}